Optimal. Leaf size=444 \[ -\frac{b^{5/2} \left (46 a^2 b^2+63 a^4+15 b^4\right ) \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{\tan (c+d x)}}{\sqrt{a}}\right )}{4 a^{7/2} d \left (a^2+b^2\right )^3}+\frac{(a-b) \left (a^2+4 a b+b^2\right ) \tan ^{-1}\left (1-\sqrt{2} \sqrt{\tan (c+d x)}\right )}{\sqrt{2} d \left (a^2+b^2\right )^3}-\frac{(a-b) \left (a^2+4 a b+b^2\right ) \tan ^{-1}\left (\sqrt{2} \sqrt{\tan (c+d x)}+1\right )}{\sqrt{2} d \left (a^2+b^2\right )^3}+\frac{b^2 \left (13 a^2+5 b^2\right )}{4 a^2 d \left (a^2+b^2\right )^2 \sqrt{\tan (c+d x)} (a+b \tan (c+d x))}+\frac{b^2}{2 a d \left (a^2+b^2\right ) \sqrt{\tan (c+d x)} (a+b \tan (c+d x))^2}-\frac{31 a^2 b^2+8 a^4+15 b^4}{4 a^3 d \left (a^2+b^2\right )^2 \sqrt{\tan (c+d x)}}-\frac{(a+b) \left (a^2-4 a b+b^2\right ) \log \left (\tan (c+d x)-\sqrt{2} \sqrt{\tan (c+d x)}+1\right )}{2 \sqrt{2} d \left (a^2+b^2\right )^3}+\frac{(a+b) \left (a^2-4 a b+b^2\right ) \log \left (\tan (c+d x)+\sqrt{2} \sqrt{\tan (c+d x)}+1\right )}{2 \sqrt{2} d \left (a^2+b^2\right )^3} \]
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Rubi [A] time = 1.09736, antiderivative size = 444, normalized size of antiderivative = 1., number of steps used = 17, number of rules used = 13, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.565, Rules used = {3569, 3649, 3653, 3534, 1168, 1162, 617, 204, 1165, 628, 3634, 63, 205} \[ -\frac{b^{5/2} \left (46 a^2 b^2+63 a^4+15 b^4\right ) \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{\tan (c+d x)}}{\sqrt{a}}\right )}{4 a^{7/2} d \left (a^2+b^2\right )^3}+\frac{(a-b) \left (a^2+4 a b+b^2\right ) \tan ^{-1}\left (1-\sqrt{2} \sqrt{\tan (c+d x)}\right )}{\sqrt{2} d \left (a^2+b^2\right )^3}-\frac{(a-b) \left (a^2+4 a b+b^2\right ) \tan ^{-1}\left (\sqrt{2} \sqrt{\tan (c+d x)}+1\right )}{\sqrt{2} d \left (a^2+b^2\right )^3}+\frac{b^2 \left (13 a^2+5 b^2\right )}{4 a^2 d \left (a^2+b^2\right )^2 \sqrt{\tan (c+d x)} (a+b \tan (c+d x))}+\frac{b^2}{2 a d \left (a^2+b^2\right ) \sqrt{\tan (c+d x)} (a+b \tan (c+d x))^2}-\frac{31 a^2 b^2+8 a^4+15 b^4}{4 a^3 d \left (a^2+b^2\right )^2 \sqrt{\tan (c+d x)}}-\frac{(a+b) \left (a^2-4 a b+b^2\right ) \log \left (\tan (c+d x)-\sqrt{2} \sqrt{\tan (c+d x)}+1\right )}{2 \sqrt{2} d \left (a^2+b^2\right )^3}+\frac{(a+b) \left (a^2-4 a b+b^2\right ) \log \left (\tan (c+d x)+\sqrt{2} \sqrt{\tan (c+d x)}+1\right )}{2 \sqrt{2} d \left (a^2+b^2\right )^3} \]
Antiderivative was successfully verified.
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Rule 3569
Rule 3649
Rule 3653
Rule 3534
Rule 1168
Rule 1162
Rule 617
Rule 204
Rule 1165
Rule 628
Rule 3634
Rule 63
Rule 205
Rubi steps
\begin{align*} \int \frac{1}{\tan ^{\frac{3}{2}}(c+d x) (a+b \tan (c+d x))^3} \, dx &=\frac{b^2}{2 a \left (a^2+b^2\right ) d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))^2}+\frac{\int \frac{\frac{1}{2} \left (4 a^2+5 b^2\right )-2 a b \tan (c+d x)+\frac{5}{2} b^2 \tan ^2(c+d x)}{\tan ^{\frac{3}{2}}(c+d x) (a+b \tan (c+d x))^2} \, dx}{2 a \left (a^2+b^2\right )}\\ &=\frac{b^2}{2 a \left (a^2+b^2\right ) d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))^2}+\frac{b^2 \left (13 a^2+5 b^2\right )}{4 a^2 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))}+\frac{\int \frac{\frac{1}{4} \left (8 a^4+31 a^2 b^2+15 b^4\right )-4 a^3 b \tan (c+d x)+\frac{3}{4} b^2 \left (13 a^2+5 b^2\right ) \tan ^2(c+d x)}{\tan ^{\frac{3}{2}}(c+d x) (a+b \tan (c+d x))} \, dx}{2 a^2 \left (a^2+b^2\right )^2}\\ &=-\frac{8 a^4+31 a^2 b^2+15 b^4}{4 a^3 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)}}+\frac{b^2}{2 a \left (a^2+b^2\right ) d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))^2}+\frac{b^2 \left (13 a^2+5 b^2\right )}{4 a^2 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))}-\frac{\int \frac{\frac{1}{8} b \left (24 a^4+31 a^2 b^2+15 b^4\right )+a^3 \left (a^2-b^2\right ) \tan (c+d x)+\frac{1}{8} b \left (8 a^4+31 a^2 b^2+15 b^4\right ) \tan ^2(c+d x)}{\sqrt{\tan (c+d x)} (a+b \tan (c+d x))} \, dx}{a^3 \left (a^2+b^2\right )^2}\\ &=-\frac{8 a^4+31 a^2 b^2+15 b^4}{4 a^3 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)}}+\frac{b^2}{2 a \left (a^2+b^2\right ) d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))^2}+\frac{b^2 \left (13 a^2+5 b^2\right )}{4 a^2 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))}-\frac{\int \frac{a^3 b \left (3 a^2-b^2\right )+a^4 \left (a^2-3 b^2\right ) \tan (c+d x)}{\sqrt{\tan (c+d x)}} \, dx}{a^3 \left (a^2+b^2\right )^3}-\frac{\left (b^3 \left (63 a^4+46 a^2 b^2+15 b^4\right )\right ) \int \frac{1+\tan ^2(c+d x)}{\sqrt{\tan (c+d x)} (a+b \tan (c+d x))} \, dx}{8 a^3 \left (a^2+b^2\right )^3}\\ &=-\frac{8 a^4+31 a^2 b^2+15 b^4}{4 a^3 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)}}+\frac{b^2}{2 a \left (a^2+b^2\right ) d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))^2}+\frac{b^2 \left (13 a^2+5 b^2\right )}{4 a^2 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))}-\frac{2 \operatorname{Subst}\left (\int \frac{a^3 b \left (3 a^2-b^2\right )+a^4 \left (a^2-3 b^2\right ) x^2}{1+x^4} \, dx,x,\sqrt{\tan (c+d x)}\right )}{a^3 \left (a^2+b^2\right )^3 d}-\frac{\left (b^3 \left (63 a^4+46 a^2 b^2+15 b^4\right )\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{x} (a+b x)} \, dx,x,\tan (c+d x)\right )}{8 a^3 \left (a^2+b^2\right )^3 d}\\ &=-\frac{8 a^4+31 a^2 b^2+15 b^4}{4 a^3 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)}}+\frac{b^2}{2 a \left (a^2+b^2\right ) d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))^2}+\frac{b^2 \left (13 a^2+5 b^2\right )}{4 a^2 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))}+\frac{\left ((a+b) \left (a^2-4 a b+b^2\right )\right ) \operatorname{Subst}\left (\int \frac{1-x^2}{1+x^4} \, dx,x,\sqrt{\tan (c+d x)}\right )}{\left (a^2+b^2\right )^3 d}-\frac{\left ((a-b) \left (a^2+4 a b+b^2\right )\right ) \operatorname{Subst}\left (\int \frac{1+x^2}{1+x^4} \, dx,x,\sqrt{\tan (c+d x)}\right )}{\left (a^2+b^2\right )^3 d}-\frac{\left (b^3 \left (63 a^4+46 a^2 b^2+15 b^4\right )\right ) \operatorname{Subst}\left (\int \frac{1}{a+b x^2} \, dx,x,\sqrt{\tan (c+d x)}\right )}{4 a^3 \left (a^2+b^2\right )^3 d}\\ &=-\frac{b^{5/2} \left (63 a^4+46 a^2 b^2+15 b^4\right ) \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{\tan (c+d x)}}{\sqrt{a}}\right )}{4 a^{7/2} \left (a^2+b^2\right )^3 d}-\frac{8 a^4+31 a^2 b^2+15 b^4}{4 a^3 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)}}+\frac{b^2}{2 a \left (a^2+b^2\right ) d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))^2}+\frac{b^2 \left (13 a^2+5 b^2\right )}{4 a^2 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))}-\frac{\left ((a+b) \left (a^2-4 a b+b^2\right )\right ) \operatorname{Subst}\left (\int \frac{\sqrt{2}+2 x}{-1-\sqrt{2} x-x^2} \, dx,x,\sqrt{\tan (c+d x)}\right )}{2 \sqrt{2} \left (a^2+b^2\right )^3 d}-\frac{\left ((a+b) \left (a^2-4 a b+b^2\right )\right ) \operatorname{Subst}\left (\int \frac{\sqrt{2}-2 x}{-1+\sqrt{2} x-x^2} \, dx,x,\sqrt{\tan (c+d x)}\right )}{2 \sqrt{2} \left (a^2+b^2\right )^3 d}-\frac{\left ((a-b) \left (a^2+4 a b+b^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{1-\sqrt{2} x+x^2} \, dx,x,\sqrt{\tan (c+d x)}\right )}{2 \left (a^2+b^2\right )^3 d}-\frac{\left ((a-b) \left (a^2+4 a b+b^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{1+\sqrt{2} x+x^2} \, dx,x,\sqrt{\tan (c+d x)}\right )}{2 \left (a^2+b^2\right )^3 d}\\ &=-\frac{b^{5/2} \left (63 a^4+46 a^2 b^2+15 b^4\right ) \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{\tan (c+d x)}}{\sqrt{a}}\right )}{4 a^{7/2} \left (a^2+b^2\right )^3 d}-\frac{(a+b) \left (a^2-4 a b+b^2\right ) \log \left (1-\sqrt{2} \sqrt{\tan (c+d x)}+\tan (c+d x)\right )}{2 \sqrt{2} \left (a^2+b^2\right )^3 d}+\frac{(a+b) \left (a^2-4 a b+b^2\right ) \log \left (1+\sqrt{2} \sqrt{\tan (c+d x)}+\tan (c+d x)\right )}{2 \sqrt{2} \left (a^2+b^2\right )^3 d}-\frac{8 a^4+31 a^2 b^2+15 b^4}{4 a^3 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)}}+\frac{b^2}{2 a \left (a^2+b^2\right ) d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))^2}+\frac{b^2 \left (13 a^2+5 b^2\right )}{4 a^2 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))}-\frac{\left ((a-b) \left (a^2+4 a b+b^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1-\sqrt{2} \sqrt{\tan (c+d x)}\right )}{\sqrt{2} \left (a^2+b^2\right )^3 d}+\frac{\left ((a-b) \left (a^2+4 a b+b^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1+\sqrt{2} \sqrt{\tan (c+d x)}\right )}{\sqrt{2} \left (a^2+b^2\right )^3 d}\\ &=\frac{(a-b) \left (a^2+4 a b+b^2\right ) \tan ^{-1}\left (1-\sqrt{2} \sqrt{\tan (c+d x)}\right )}{\sqrt{2} \left (a^2+b^2\right )^3 d}-\frac{(a-b) \left (a^2+4 a b+b^2\right ) \tan ^{-1}\left (1+\sqrt{2} \sqrt{\tan (c+d x)}\right )}{\sqrt{2} \left (a^2+b^2\right )^3 d}-\frac{b^{5/2} \left (63 a^4+46 a^2 b^2+15 b^4\right ) \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{\tan (c+d x)}}{\sqrt{a}}\right )}{4 a^{7/2} \left (a^2+b^2\right )^3 d}-\frac{(a+b) \left (a^2-4 a b+b^2\right ) \log \left (1-\sqrt{2} \sqrt{\tan (c+d x)}+\tan (c+d x)\right )}{2 \sqrt{2} \left (a^2+b^2\right )^3 d}+\frac{(a+b) \left (a^2-4 a b+b^2\right ) \log \left (1+\sqrt{2} \sqrt{\tan (c+d x)}+\tan (c+d x)\right )}{2 \sqrt{2} \left (a^2+b^2\right )^3 d}-\frac{8 a^4+31 a^2 b^2+15 b^4}{4 a^3 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)}}+\frac{b^2}{2 a \left (a^2+b^2\right ) d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))^2}+\frac{b^2 \left (13 a^2+5 b^2\right )}{4 a^2 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))}\\ \end{align*}
Mathematica [C] time = 3.95141, size = 358, normalized size = 0.81 \[ \frac{\frac{13 a^2 b^2+5 b^4}{a \left (a^2+b^2\right ) (a+b \tan (c+d x))}+\frac{-63 a^4 b^{5/2} \sqrt{\tan (c+d x)} \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{\tan (c+d x)}}{\sqrt{a}}\right )-46 a^2 b^{9/2} \sqrt{\tan (c+d x)} \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{\tan (c+d x)}}{\sqrt{a}}\right )-39 a^{9/2} b^2-46 a^{5/2} b^4-4 (-1)^{3/4} a^{7/2} (a+i b)^3 \tan ^{-1}\left ((-1)^{3/4} \sqrt{\tan (c+d x)}\right ) \sqrt{\tan (c+d x)}-4 \sqrt [4]{-1} a^{7/2} (b+i a)^3 \sqrt{\tan (c+d x)} \tanh ^{-1}\left ((-1)^{3/4} \sqrt{\tan (c+d x)}\right )-8 a^{13/2}-15 b^{13/2} \sqrt{\tan (c+d x)} \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{\tan (c+d x)}}{\sqrt{a}}\right )-15 \sqrt{a} b^6}{a^{5/2} \left (a^2+b^2\right )^2}+\frac{2 b^2}{(a+b \tan (c+d x))^2}}{4 a d \left (a^2+b^2\right ) \sqrt{\tan (c+d x)}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.045, size = 920, normalized size = 2.1 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.65231, size = 734, normalized size = 1.65 \begin{align*} -\frac{{\left (\sqrt{2} a^{3} + 3 \, \sqrt{2} a^{2} b - 3 \, \sqrt{2} a b^{2} - \sqrt{2} b^{3}\right )} \arctan \left (\frac{1}{2} \, \sqrt{2}{\left (\sqrt{2} + 2 \, \sqrt{\tan \left (d x + c\right )}\right )}\right )}{2 \,{\left (a^{6} d + 3 \, a^{4} b^{2} d + 3 \, a^{2} b^{4} d + b^{6} d\right )}} - \frac{{\left (\sqrt{2} a^{3} + 3 \, \sqrt{2} a^{2} b - 3 \, \sqrt{2} a b^{2} - \sqrt{2} b^{3}\right )} \arctan \left (-\frac{1}{2} \, \sqrt{2}{\left (\sqrt{2} - 2 \, \sqrt{\tan \left (d x + c\right )}\right )}\right )}{2 \,{\left (a^{6} d + 3 \, a^{4} b^{2} d + 3 \, a^{2} b^{4} d + b^{6} d\right )}} + \frac{{\left (\sqrt{2} a^{3} - 3 \, \sqrt{2} a^{2} b - 3 \, \sqrt{2} a b^{2} + \sqrt{2} b^{3}\right )} \log \left (\sqrt{2} \sqrt{\tan \left (d x + c\right )} + \tan \left (d x + c\right ) + 1\right )}{4 \,{\left (a^{6} d + 3 \, a^{4} b^{2} d + 3 \, a^{2} b^{4} d + b^{6} d\right )}} - \frac{{\left (\sqrt{2} a^{3} - 3 \, \sqrt{2} a^{2} b - 3 \, \sqrt{2} a b^{2} + \sqrt{2} b^{3}\right )} \log \left (-\sqrt{2} \sqrt{\tan \left (d x + c\right )} + \tan \left (d x + c\right ) + 1\right )}{4 \,{\left (a^{6} d + 3 \, a^{4} b^{2} d + 3 \, a^{2} b^{4} d + b^{6} d\right )}} - \frac{{\left (63 \, a^{4} b^{3} + 46 \, a^{2} b^{5} + 15 \, b^{7}\right )} \arctan \left (\frac{b \sqrt{\tan \left (d x + c\right )}}{\sqrt{a b}}\right )}{4 \,{\left (a^{9} d + 3 \, a^{7} b^{2} d + 3 \, a^{5} b^{4} d + a^{3} b^{6} d\right )} \sqrt{a b}} - \frac{15 \, a^{2} b^{4} \tan \left (d x + c\right )^{\frac{3}{2}} + 7 \, b^{6} \tan \left (d x + c\right )^{\frac{3}{2}} + 17 \, a^{3} b^{3} \sqrt{\tan \left (d x + c\right )} + 9 \, a b^{5} \sqrt{\tan \left (d x + c\right )}}{4 \,{\left (a^{7} d + 2 \, a^{5} b^{2} d + a^{3} b^{4} d\right )}{\left (b \tan \left (d x + c\right ) + a\right )}^{2}} - \frac{2}{a^{3} d \sqrt{\tan \left (d x + c\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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